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35m^2-160m+86=0
a = 35; b = -160; c = +86;
Δ = b2-4ac
Δ = -1602-4·35·86
Δ = 13560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13560}=\sqrt{4*3390}=\sqrt{4}*\sqrt{3390}=2\sqrt{3390}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-2\sqrt{3390}}{2*35}=\frac{160-2\sqrt{3390}}{70} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+2\sqrt{3390}}{2*35}=\frac{160+2\sqrt{3390}}{70} $
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